это дробь...

Adam123RUS @Adam123RUS

July 2022 2 12 Report

(х+3)(4х-1)/х+5<0 помогите решить неравенство методом интервала
/ это дробь

xtoto (x+3)*(4x-1)/(x+5)<0 ОДЗ: x+5≠0 x≠-5
-∞____-____-5____+____-3____-____1/4____+____+∞
Ответ: x∈(-∞;-5)U(-3;1/4).

6 votes Thanks 6

Adam123RUS спасибо

xtoto пожалуйста

sangers1959

Verified answer

$\frac{(x+3)(4x-1)}{x+5}\ \textless \ 0\\\\
\frac{(x+3)*(4x-1)}{x+5}\ \textless \ 0\\\\
\frac{(x+3)*4*(x-\frac{1}{4})}{x+5}\ \textless \ 0\\\\
\frac{(x+3)*(x-\frac{1}{4})}{x+5}\ \textless \ 0\\\\
\frac{[x-(-3)]*[x-\frac{1}{4}]}{x-(-5)}\ \textless \ 0\\\\
-----(-5)+++++[-3]------[-\frac{1}{4}]+++++\ \textgreater \ x\\\\
x\in(-\infty;\ -5)\cup[\frac{1}{4};\ +\infty)$

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