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u4eniza2015
@u4eniza2015
July 2022
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Решите,а?!
1)0,027а^12+b^9
2)20z^2+3xy-15xz-4yz
3)-9/64n^6-3mn^5-16m^2n^4
? / ?(это обыкновенная дробь).; ?^(это знак степени)
Помогите,даю 20 баллов)))
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nafanya2014
Verified answer
1)0,027а¹²+b^9=(0,3а⁴)³+(b³)³=(0,3a⁴+b³)(0,09a⁸-0,3a⁴b³+b⁶)
2)20z²+3xy-15xz-4yz=(20z²-15xz)-(4yz-3xz)=5z(4z-3x)-y(4z-3x)=(4z-3x)(5z-y)
3)
4 votes
Thanks 4
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Answers & Comments
Verified answer
1)0,027а¹²+b^9=(0,3а⁴)³+(b³)³=(0,3a⁴+b³)(0,09a⁸-0,3a⁴b³+b⁶)2)20z²+3xy-15xz-4yz=(20z²-15xz)-(4yz-3xz)=5z(4z-3x)-y(4z-3x)=(4z-3x)(5z-y)
3)