Ответ:
[tex]\frac{3a^3+ab^2-6a^2b-2b^3}{9a^5-ab^4-18a^4b+2b^5}=\frac{1}{3a^2-b^2}[/tex]
Объяснение:
[tex]\frac{3a^3+ab^2-6a^2b-2b^3}{9a^5-ab^4-18a^4b+2b^5}=[/tex]
[tex]\frac{a(3a^2+b^2)-2b(3a^2+b^2)}{9a^5-18a^4b-ab^4+2b^5}=[/tex]
[tex]\frac{(3a^2+b^2)(a-2b)}{9a^4(a-2b)-b^4(a-2b)}=[/tex]
[tex]\frac{(3a^2+b^2)(a-2b)}{(a-2b)(9a^4-b^4)}=[/tex]
[tex]\frac{3a^2+b^2}{9a^4-b^4}=[/tex]
[tex]\frac{3a^2+b^2}{(3a^2)^2-(b^2)^2}=[/tex]
[tex]\frac{3a^2+b^2}{(3a^2-b^2)(3a^2+b^2)}=[/tex]
[tex]\frac{1}{3a^2-b^2}[/tex]
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Answers & Comments
Ответ:
[tex]\frac{3a^3+ab^2-6a^2b-2b^3}{9a^5-ab^4-18a^4b+2b^5}=\frac{1}{3a^2-b^2}[/tex]
Объяснение:
[tex]\frac{3a^3+ab^2-6a^2b-2b^3}{9a^5-ab^4-18a^4b+2b^5}=[/tex]
[tex]\frac{a(3a^2+b^2)-2b(3a^2+b^2)}{9a^5-18a^4b-ab^4+2b^5}=[/tex]
[tex]\frac{(3a^2+b^2)(a-2b)}{9a^4(a-2b)-b^4(a-2b)}=[/tex]
[tex]\frac{(3a^2+b^2)(a-2b)}{(a-2b)(9a^4-b^4)}=[/tex]
[tex]\frac{3a^2+b^2}{9a^4-b^4}=[/tex]
[tex]\frac{3a^2+b^2}{(3a^2)^2-(b^2)^2}=[/tex]
[tex]\frac{3a^2+b^2}{(3a^2-b^2)(3a^2+b^2)}=[/tex]
[tex]\frac{1}{3a^2-b^2}[/tex]