Ответ:

а)

[tex]\frac{2x+4}{x-1} = \frac{2x-2+6}{x-1} = 2+\frac{4}{x-1}[/tex]

[tex]\frac{4}{x-1}[/tex] должно делиться нацело

x-1 = 1

x = 2

x-1 = -1

x = 0

x-1 = 2

x = 3

x-1 = -2

x = -1

x-1 = 4

x = 5

x-1 = -4

x = -3

Ответ: х = 2; 0; 3; -1; 5; -3

б)

[tex]\frac{5x^{2} +x-10}{x+2} = 5x-9+\frac{8}{x+2}[/tex]

аналогично \frac{8}{x+2} должно делиться нацело

x+2 = 1

x = -1

x+2 = -1

x=-3

x+2 = 2

x = 0

x+2 = -2

x = -4

x+2 = 4

x = 2

x+2 = -4

x = -6

x+2 = 8

x = 6

x+2 = -8

x = -10

ответ х = -1; -3; 0; -4; 2 ; -6; 6; -10