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Ответ:

[tex]\boxed{\ (a-b)^2=a^2-2ab+b^2\ }[/tex]

[tex]x=\dfrac{3}{8}\ \ ,\ \ (4-x)^2-x(x+6)=16-8x+x^2-x^2-6x=16-14x=\\\\=16-14\cdot \dfrac{3}{8}=16-\dfrac{7\cdot 3}{4}=\dfrac{43}{4}=10,75[/tex]

Ответ:

Вот лови.

I hope it helped.

Bye Bye.