Ршение.

Точка пересечения - решение системы уравнений

[tex]\left\{\begin{array}{l}y=-x^2\\y=\dfrac{8}{x}\end{array}\right\ \ \left\{\begin{array}{l}-x^2=\dfrac{8}{x}\\\ \, y=-x^2\end{array}\right\ \ \left\{\begin{array}{l}-x^3-8=0\\x\ne 0\\y=-x^2\end{array}\right\ \ \left\{\begin{array}{l}x^2+8=0\\x\ne 0\\y=-x^2\end{array}\right\\\\\\\left\{\begin{array}{l}(x+2)(x^2-2x+4)=0\\x\ne 0\\y=-x^2\end{array}\right\ \ \left\{\begin{array}{l}x=-2\\x\ne 0\\y=-(-2)^2\end{array}\right\ \ \left\{\begin{array}{l}x=-2\\x\ne 0\\y=-4\end{array}\right[/tex]

Ответ: №3 ,   [tex]A(-2\, ;-4\, )\ .[/tex]