Ответ: 4. y=2-xy'= d/dx(2-x)y'= d/dx(2)-d/dx(x)y'=0-d/dx(x)y'=0-1y'=-1
5. [tex]\left \{ {{3x+y=14} \atop {5x-y=10}} \right. \\\left \{ {{y=14-3x} \atop {5x-y=10}} \right. \\5x-(14-3x)=10\\5x-(14-3x)=10\\5x-14+3x=10\\8x-14=10\\8x=10+14\\\8x=24\\x=3\\y=14-3*3\\y=14-9\\y=5\\(x,y)=(3,5)\\\left \{ {{3*3+5=14} \atop5*3-5=10}} \right. \\\left \{ {{14=14} \atop {10=10}} \right. \\(x,y)=(3,5)\\\\6. 4x-4y+x^{2}-2xy+y^{2} \\4(x-y)+x^{2} -2xy+y^{2} 4(x-y)+(x-y)^{2} \\(x-y)*(4+x-y)[/tex]
Объяснение:
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Ответ: 4. y=2-x
y'= d/dx(2-x)
y'= d/dx(2)-d/dx(x)
y'=0-d/dx(x)
y'=0-1
y'=-1
5. [tex]\left \{ {{3x+y=14} \atop {5x-y=10}} \right. \\\left \{ {{y=14-3x} \atop {5x-y=10}} \right. \\5x-(14-3x)=10\\5x-(14-3x)=10\\5x-14+3x=10\\8x-14=10\\8x=10+14\\\8x=24\\x=3\\y=14-3*3\\y=14-9\\y=5\\(x,y)=(3,5)\\\left \{ {{3*3+5=14} \atop5*3-5=10}} \right. \\\left \{ {{14=14} \atop {10=10}} \right. \\(x,y)=(3,5)\\\\6. 4x-4y+x^{2}-2xy+y^{2} \\4(x-y)+x^{2} -2xy+y^{2} 4(x-y)+(x-y)^{2} \\(x-y)*(4+x-y)[/tex]
Объяснение: