Ответ:
Mr[FeSO4*7H2O] = Ar[Fe] + Ar[H] * 14 + Ar[O] * 11 + Ar[S] = 56 + 1 * 14 + 16 * 11 + 32 = 278
ω (Fe) = 56 : 278 * 100 = 20 %
Объяснение:
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Ответ:
Mr[FeSO4*7H2O] = Ar[Fe] + Ar[H] * 14 + Ar[O] * 11 + Ar[S] = 56 + 1 * 14 + 16 * 11 + 32 = 278
ω (Fe) = 56 : 278 * 100 = 20 %
Объяснение: