√2*cos(x/2 + 3) + 1 = 0√2*cos(x/2 + 3) = - 1 cos(x/2 + 3) = - 1/√2 cos(x/2 + 3) = - √2/2x/2 + 3 = ± 3π/4 + 2πk k ∈ Z x/2 = ± 3π/4 - 3 + 2πk k ∈ Z x = ± 3π/2 - 6 + 4πk k ∈ Z
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Answers & Comments
√2*cos(x/2 + 3) + 1 = 0
√2*cos(x/2 + 3) = - 1
cos(x/2 + 3) = - 1/√2
cos(x/2 + 3) = - √2/2
x/2 + 3 = ± 3π/4 + 2πk k ∈ Z
x/2 = ± 3π/4 - 3 + 2πk k ∈ Z
x = ± 3π/2 - 6 + 4πk k ∈ Z