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Vas918amg
@Vas918amg
June 2022
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„Формула корней квадратных уравнений“. 1) (3x-1)(x+2)=20; 2) (x-4)(4x-3)+3=0.
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sakuru
Второго не могла решить
1 votes
Thanks 1
Checov7400
(х-4)(4х-3)+3=0
4х²-3х-16х+12+3=0
4х²-19х+15=0
D=(19)²-4*4*15=361-240=121
х1=(19+√121)/8=30/8=3 3/4
х2=(19-11)/8=1
(3х-1)(х+2)=20
3х²+6х-х-2=20
3х²+5х-22=0
D=25+4*66=25+264=289
х1=(-5+√289)/6 х1=(-5+17)/6=2 х2=(-5-17)/6=-22/6=-3 2/3
2 votes
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Answers & Comments
4х²-3х-16х+12+3=0
4х²-19х+15=0
D=(19)²-4*4*15=361-240=121
х1=(19+√121)/8=30/8=3 3/4
х2=(19-11)/8=1
(3х-1)(х+2)=20
3х²+6х-х-2=20
3х²+5х-22=0
D=25+4*66=25+264=289
х1=(-5+√289)/6 х1=(-5+17)/6=2 х2=(-5-17)/6=-22/6=-3 2/3