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LadnoOK
@LadnoOK
July 2022
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Формулы двойного и половинного угла. Тригонометрия
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Влада1414
Для двойного:
cos 2α = cos2α – sin2α = 2 cos2α – 1 = 1 – 2sin2α
для половинного: tg2α/2 = (1 – cos α)/(1 + cos α)ctg2α/2 = (1 + cos α)/(1 – cos α)tg α/2 = sin α/(1 + cos α)cos α = (1 – tg2α/2)/(1 + tg2α/2)sin α = (2 tg α/2)/(1 + tg2α/2)
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xtgxtyrj
1) 1-tg²x=cos2*x/cos²x тогда получаем 2*sinx/cosx*cos²x/cos2*x=tg2*x
1+cos4x=cos²2*x+sin²2*x+cos²2*x-sin²2*x=2*cos²2*x преобразовываем
(tg2*x)*2*cos²2*x=sin4*x
2)cosx/sinx-2sinx*coxs=cosx/sinx*(1-2*sin²x)=ctgx(cos²x+sin²x-2*sin²x)=ctgx*(cos²x-sin²x)=ctg*cos2x
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Answers & Comments
cos 2α = cos2α – sin2α = 2 cos2α – 1 = 1 – 2sin2α
для половинного: tg2α/2 = (1 – cos α)/(1 + cos α)ctg2α/2 = (1 + cos α)/(1 – cos α)tg α/2 = sin α/(1 + cos α)cos α = (1 – tg2α/2)/(1 + tg2α/2)sin α = (2 tg α/2)/(1 + tg2α/2)
1+cos4x=cos²2*x+sin²2*x+cos²2*x-sin²2*x=2*cos²2*x преобразовываем
(tg2*x)*2*cos²2*x=sin4*x
2)cosx/sinx-2sinx*coxs=cosx/sinx*(1-2*sin²x)=ctgx(cos²x+sin²x-2*sin²x)=ctgx*(cos²x-sin²x)=ctg*cos2x