Ответ:
[tex](\frac{a}{a-b}-\frac{a}{a+b})*\frac{a+b}{2b}=\frac{a}{a-b}[/tex]
[tex]1)\frac{a}{a-b}-\frac{a}{a+b} =\frac{a(a+b)-a(a-b)}{(a-b)(a+b)}=\frac{a^{2}+ab-a^{2}+ab }{(a-b)(a+b)}=\frac{2ab}{(a-b)(a+b)}[/tex]
[tex]2)\frac{2ab}{(a-b)(a+b)}*\frac{a+b}{2b}=\frac{2ab*(a+b)}{(a-b)(a+b)*2b}=\frac{a}{a-b}[/tex]
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Ответ:
[tex](\frac{a}{a-b}-\frac{a}{a+b})*\frac{a+b}{2b}=\frac{a}{a-b}[/tex]
[tex]1)\frac{a}{a-b}-\frac{a}{a+b} =\frac{a(a+b)-a(a-b)}{(a-b)(a+b)}=\frac{a^{2}+ab-a^{2}+ab }{(a-b)(a+b)}=\frac{2ab}{(a-b)(a+b)}[/tex]
[tex]2)\frac{2ab}{(a-b)(a+b)}*\frac{a+b}{2b}=\frac{2ab*(a+b)}{(a-b)(a+b)*2b}=\frac{a}{a-b}[/tex]