F'(x) = ((x+1)√x)' = (x+1)'√x+(x+1)(√x)' = √x+(x+1)/(2√x)
F'(x)= 1*√x+ (x+1)/2√x = √x+(x+1)/2√x = ( 2x+x+1)/2√x= (3x+1)/2√x
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F'(x) = ((x+1)√x)' = (x+1)'√x+(x+1)(√x)' = √x+(x+1)/(2√x)
F'(x)= 1*√x+ (x+1)/2√x = √x+(x+1)/2√x = ( 2x+x+1)/2√x= (3x+1)/2√x