Ответ:
f ' (x) = (4x + 2x^2) ' = (4x) ' + (2x^2) ' = 4 (x) ' + 2 (x^2) ' =
= 4*1 + 2*2x = 4 + 4x
f ' (x) ≤ 0
4x + 4 ≤ 0 / : 4
x + 1≤ 0
x ≤ - 1
x ∈ ( - ∞; - 1]
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Ответ:
f ' (x) = (4x + 2x^2) ' = (4x) ' + (2x^2) ' = 4 (x) ' + 2 (x^2) ' =
= 4*1 + 2*2x = 4 + 4x
f ' (x) ≤ 0
4x + 4 ≤ 0 / : 4
x + 1≤ 0
x ≤ - 1
x ∈ ( - ∞; - 1]