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adidas2963
@adidas2963
July 2022
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F(x)=(2x-П)*sin3x в точке X0=П
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ПрофиЗнания
F'(x)=(2x-
П)' *sin3x+ (2x-
П)*(sin3x)' * (3x)' = 2sin3x+(2x-
П)*3cos3x
Производная в точке х₀=
П
F(x0)=2sin3П+(2П-П)*3cos3П = 2sin3П+П*3cos3
П=
2sin3
П=2sin(3*180)=2sin180=2*0=0
3cos3
П=3cos(3*180)=3cos180=3*(-1)=-3
=0+
П*(-3)=-3
П
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Answers & Comments
Производная в точке х₀=П
F(x0)=2sin3П+(2П-П)*3cos3П = 2sin3П+П*3cos3П=
2sin3П=2sin(3*180)=2sin180=2*0=0
3cos3П=3cos(3*180)=3cos180=3*(-1)=-3
=0+П*(-3)=-3П