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keklol2015
@keklol2015
July 2022
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f(x)=(2+x^2)\x^3. Найдите f`(-1\sqrt2)
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ПрофиЗнания
F'(x)= 2x*x³-(2+x²)*3x² / x⁶ = 2x⁴-6x²-3x⁴/x⁶=-6x²-x⁴/x⁶ = -6-x²/x⁴
f'(-1/√2) = -6-1/2 / 1/4 = -6 1/2 *4 =- 13/2 *4 = -26
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Answers & Comments
f'(-1/√2) = -6-1/2 / 1/4 = -6 1/2 *4 =- 13/2 *4 = -26