f(x)=x^3+0,5x^2-4x+2 , f'(x)

August 2022 1 3 Report

f(x)=x^3+0,5x^2-4x+2 , f'(x)<=0

Answers & Comments

Мадына F'(x)= 3x^2+x-4+0=3x^2+x-4
3x^2+x-4<=0
D= 1+48=49
X1= (1-7)/6=-1
X2=(1+7)/6=4/3
[-1;4/3]

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