Ответ:
0
Пошаговое объяснение:
[tex]F(x)=x^3+3x^2-9x-1\\\\f(x)=F`(x)=(x^3+3x^2-9x-1)`=3x^2+6x-9\\\\F(4)=4^3+3*4^2-9*4-1=64+48-36-1=75\\\\f(-3)=3*(-3)^2+6*(-3)-9=27-18-9=0\\\\F(4)*f(-3)=75*0=0[/tex]
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Ответ:
0
Пошаговое объяснение:
[tex]F(x)=x^3+3x^2-9x-1\\\\f(x)=F`(x)=(x^3+3x^2-9x-1)`=3x^2+6x-9\\\\F(4)=4^3+3*4^2-9*4-1=64+48-36-1=75\\\\f(-3)=3*(-3)^2+6*(-3)-9=27-18-9=0\\\\F(4)*f(-3)=75*0=0[/tex]