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July 2022
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геометрическая прогрессия bn задана условиями b1=-7 bn+1=2b найти сумму первых шести ее членов
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Pacanka202
Verified answer
B2=2*(-7)=-14
q=b2/b1=-14/-7=2
S6=b1(q^6–1)/(q–1)=(-7*63)/1=-441
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Verified answer
B2=2*(-7)=-14q=b2/b1=-14/-7=2
S6=b1(q^6–1)/(q–1)=(-7*63)/1=-441