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zolotaat
@zolotaat
July 2022
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Геометрична прогресія
(bn) :q=2 n=7 S7=635 знайти b1 b7
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sedinalana
S7=b1*(q^7 -1)/(q-1)
b1*(128-1)/(2-1)=635
127*b1=635
b1=635:127
b1=5
bn=b1*q^n-1
b7=5*2^6
b1=5*64
b1=320
5 votes
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Answers & Comments
b1*(128-1)/(2-1)=635
127*b1=635
b1=635:127
b1=5
bn=b1*q^n-1
b7=5*2^6
b1=5*64
b1=320