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memesnoshemes
@memesnoshemes
August 2022
1
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геометрия................,..............
ответ 1,5 через подобие
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kirichekov
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<ANB=<NBD накрест лежащие при BC||AD и секущей AN
<DBN=<BDA накрест лежащие при BC||AD и секущей BC
<BQN=<AQD вертикальные⇒
ΔDQA подобен ΔBQN
BC=BN+NC
BC=3x ⇒ AD=3x
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Verified answer
<ANB=<NBD накрест лежащие при BC||AD и секущей AN<DBN=<BDA накрест лежащие при BC||AD и секущей BC
<BQN=<AQD вертикальные⇒
ΔDQA подобен ΔBQN
BC=BN+NC
BC=3x ⇒ AD=3x