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Rinan2000
@Rinan2000
July 2022
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ГОНОЧНЫЙ АВТОМОБИЛЬ t,сек- 3,4, V км\ч=110 Найти: a-?(ускорение) и S-?(расстояние)
ПОМОГИТЕ ПОЖАЛУЙСТА, СРОЧНО НУЖНОООООООООООО:)
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tana20101997
Verified answer
A=V/t=30,56/3,4=8,99 м/с2
S=V^2/2*a=933,9/2*8,99=51,9 м
0 votes
Thanks 1
Crcentr
V=a*t
110 км/ч=275/9 м/с
275/9=a*3.4
a=8.987 м/с^2
S=a*t^2/2=8.987*(3.4)^2=103.89 м
0 votes
Thanks 1
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Answers & Comments
Verified answer
A=V/t=30,56/3,4=8,99 м/с2S=V^2/2*a=933,9/2*8,99=51,9 м
110 км/ч=275/9 м/с
275/9=a*3.4
a=8.987 м/с^2
S=a*t^2/2=8.987*(3.4)^2=103.89 м