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marianna1252
@marianna1252
July 2022
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график функции y=kx+l проходит через точки А(0;-3) В(2;1) Найдите k и l
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karmelita1953
K*0+L=-3⇒L=- 3
2k+L=1⇒2k-3=1⇒2k=4⇒k=2
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Answers & Comments
2k+L=1⇒2k-3=1⇒2k=4⇒k=2