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Lıttlestar
@Lıttlestar
July 2022
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Помогите пожалуйста. Срочно. Решите уравнение <br /> 2 cos^2x+3cosx-2=0
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sedinalana
Verified answer
Cosx=a
2a²+3a-2=0
D=9+16=25
a1=(-3-5)/4=-2⇒cosx=-2<-1 нет решения
a2=(-3+5)/4=1/2⇒cosx=1/2⇒x=+-π/3+2πn,n∈z
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Verified answer
Cosx=a2a²+3a-2=0
D=9+16=25
a1=(-3-5)/4=-2⇒cosx=-2<-1 нет решения
a2=(-3+5)/4=1/2⇒cosx=1/2⇒x=+-π/3+2πn,n∈z