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VeraFrik
@VeraFrik
August 2022
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Решите модульное уравнение
|x-3|/(|х-2|-1)=1
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Verified answer
|x-3|/(|x-2|-1)=1
ОДЗ:
|x-2|-1≠0
|x-2|≠1
х-2≠1 и х-2≠-1
х≠3 х≠1
|x-3|=|x-2|-1 __________2____________3___________
1) x<2 2) 2≤x<3 3) x≥3
3-x=2-x-1 3-x=x-2-1 x-3=x-2-1
0x=-2 2x=6 0x=0
x∈∅ x=3 ∉ОДЗ x- любое число из (3;+∞)
Ответ: (3;+∞)
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Answers & Comments
Verified answer
|x-3|/(|x-2|-1)=1ОДЗ:
|x-2|-1≠0
|x-2|≠1
х-2≠1 и х-2≠-1
х≠3 х≠1
|x-3|=|x-2|-1 __________2____________3___________
1) x<2 2) 2≤x<3 3) x≥3
3-x=2-x-1 3-x=x-2-1 x-3=x-2-1
0x=-2 2x=6 0x=0
x∈∅ x=3 ∉ОДЗ x- любое число из (3;+∞)
Ответ: (3;+∞)