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rryyrrrttt
@rryyrrrttt
August 2022
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Решите уравнение х^2-10х+16/х-2=0
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прр40
(x²-10x+16)/(x-2)=0
ОДЗ: х-2≠0 х≠2
x²-10x+16=0 D=36
x₁=8 ∈ОДЗ x₂=2 ∉ОДЗ
Ответ: х=8.
0 votes
Thanks 1
sangers1959
Verified answer
Х²-10х+16/х-2=0
ОДЗ: х≠2
х²-10х+16=0
D=100-4*16=100-64=36
x= 10+6/2=16/2=8
x=10-6/2=4/2=2(искл., т.к не удовл ОДЗ)
Ответ: 8
1 votes
Thanks 1
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Answers & Comments
ОДЗ: х-2≠0 х≠2
x²-10x+16=0 D=36
x₁=8 ∈ОДЗ x₂=2 ∉ОДЗ
Ответ: х=8.
Verified answer
Х²-10х+16/х-2=0ОДЗ: х≠2
х²-10х+16=0
D=100-4*16=100-64=36
x= 10+6/2=16/2=8
x=10-6/2=4/2=2(искл., т.к не удовл ОДЗ)
Ответ: 8