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asyutka
@asyutka
August 2022
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помогите пожалуйста:
2х/х^2-4 = х/х+2 - 1/х-2
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Valeriya1701
2х/х²-4-х/х+2+1/х-2=0
2х-х²+2х+х+2/х²-4=0
-х²+5х+2/х²-4=0
х²-5х-2=0. х²-4≠0
д=√33 х=5±√33/2. х≠±2
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Answers & Comments
2х-х²+2х+х+2/х²-4=0
-х²+5х+2/х²-4=0
х²-5х-2=0. х²-4≠0
д=√33 х=5±√33/2. х≠±2