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businka2103
@businka2103
August 2022
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Помогите решить уравнение:
12/(х+4)+4/(х-4)=2
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ShirokovP
Verified answer
ОДЗ:
x ≠ - 4
x ≠ 4
12(x - 4) + 4(x + 4) = 2(x - 4)* (x + 4)
12x - 48 + 4x + 16 = 2(x^2 - 16)
16x - 32 = 2x^2 - 32
- 32 и - 32 уничтожаются
2x^2 = 16x // : 2
x^2 = 8x
x^2 - 8x = 0
неполное квадратное
x (x - 8) = 0
x1 = 0
x2 = 8
Ответ:
0 ; 8
3 votes
Thanks 1
businka2103
ооо,все поняла,большое спасибо))
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Answers & Comments
Verified answer
ОДЗ:x ≠ - 4
x ≠ 4
12(x - 4) + 4(x + 4) = 2(x - 4)* (x + 4)
12x - 48 + 4x + 16 = 2(x^2 - 16)
16x - 32 = 2x^2 - 32
- 32 и - 32 уничтожаются
2x^2 = 16x // : 2
x^2 = 8x
x^2 - 8x = 0
неполное квадратное
x (x - 8) = 0
x1 = 0
x2 = 8
Ответ:
0 ; 8