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Нелька14
@Нелька14
July 2022
2
12
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х²-4√3х+12=0
как решить?
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Ellenochka
Х²-4√3х+12=0
это уравнение с квадратом разности
, где:
х²-4√3х+12=х²-2*(2√3)*х+(2√3)²=(х-2√3)² ;
(х-2√3)² =0
х-2√3 = 0
х = 2√3
1 votes
Thanks 1
Kdrew
Х²-4√3х+12
Д=48-48=0
х=-b/2a
х=4√3/2=2√3
ОТВЕТ:2√3
1 votes
Thanks 1
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Answers & Comments
это уравнение с квадратом разности , где:
х²-4√3х+12=х²-2*(2√3)*х+(2√3)²=(х-2√3)² ;
(х-2√3)² =0
х-2√3 = 0
х = 2√3
Д=48-48=0
х=-b/2a
х=4√3/2=2√3
ОТВЕТ:2√3