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Melleri
@Melleri
August 2022
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х³-64х=0 Найти все корни
x³-8x²+16x Разложить на множатели
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belcatya
1)
х³-64х=0
x³-64x=0
x(x²-8²)=0
x(x-8)(x+8)=0
x₁=0
x₂=-8
x₃=8
2)
x³-8x²+16x
=x(x²-8x+16)=x(x²-2*4*x+4²)=x(x-4)²
1 votes
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Answers & Comments
х³-64х=0
x³-64x=0
x(x²-8²)=0
x(x-8)(x+8)=0
x₁=0
x₂=-8
x₃=8
2)
x³-8x²+16x=x(x²-8x+16)=x(x²-2*4*x+4²)=x(x-4)²