х во 2 - 25 1 х+5 ------------- * ------------ - --------------- х+6 х во 2 +5х х во 2 - 6х х+3 ( х+3 х-3) при х равно : 1,75. 1,6. -1,6. 0,8. -0,8 -------- * ------------+-------- х во2 +9 (х-3 х+3). Created by Викториночка2. matematika-ru

х во 2 - 25 1 х+5 ------------- * ------------ - --------------- х+6 х во 2 +5х ...

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х во 2 - 25 1 х+5
------------- * ------------ - ---------------
х+6 х во 2 +5х х во 2 - 6х

х+3 ( х+3 х-3) при х равно : 1,75. 1,6. -1,6. 0,8. -0,8
-------- * ------------+--------
х во2 +9 (х-3 х+3)

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zhenyaM2002

Verified answer

$\frac{x^2-25}{x+6} * \frac{1}{x^2+5x} - \frac{x+5}{x^2-6x} = \\ \\ 
= \frac{(x-5)(x+5) * 1 }{(x+6) * x(x+5) } - \frac{x+5}{x(x-6)} = \\ \\ 
= \frac{x-5}{x(x+6)} - \frac{x+5}{x(x-6)} = \\ \\ 
= \frac{(x-5)(x-6) - (x+5)(x+6)}{x(x+6)(x-6)} = \\ \\ 
= \frac{x^2-6x-5x+30 - x^2-6x-5x-30}{x(x^2-6^2)} = \\ \\ 
= \frac{-22x}{x(x^2-36)} = - \frac{22}{x^2-36}$
Ответ : 4)

$\frac{x+3}{x^2 + 9 } * ( \frac{x+3}{x-3} + \frac{x-3}{x+3} )= \\ \\ 
= \frac{x+3}{x^2 + 9} * \frac{(x+3)(x+3) + (x-3)(x-3)}{(x-3)(x+3)} = \\ \\ 
= \frac{x+3}{x^2 + 3^2} * \frac{(x+3)^2 +(x-3)^2}{x^2 - 3^2} = \\ \\ 
= \frac{x+3}{x^2 + 3^2} * \frac{x^2 +6x+3^2 + x^2 -6x+3^2}{(x^2-3^2)} = \\ \\ 
= \frac{(x+3)(2x^2+18)}{(x^2+9)(x^2-9)} = \frac{2(x+3)(x^2+9)}{(x^2+9)(x+3)(x-3)} = \\ \\ 
= \frac{2}{x-3} \\ \\ 
x=1.75 \\ 
 \frac{2}{1.75 - 3} = \frac{2}{-1.25} = -1.6$
Ответ: 2)

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