(х+1) - (х-2)(х+2) =7. Created by faqq1123ru18. algebra-ru

(х+1) - (х-2)(х+2) =7...

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Ответ:

Объяснение:

(х + 1) - (х - 2)(х + 2) = 7

х + 1 - (х² - 4) = 7

х + 1 - х² + 4 = 7

x² - x + 7 - 5 = 0

x² - x + 2 = 0

D = b² - 4ac = (-1)² - 4 · 2 =1 - 8 = -7 < 0

О т в е т : в действительных числах решение нет, ∅

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Artsounds

Ответ:

$(x + 1) - (x - 2)(x + 2) = 7 \\ x + 1 - (x {}^{2} - 4) = 7 \\ x + 1 - x {}^{2} + 4 = 7 \\ x + 5 - x {}^{2} = 7 \\ x + 5 - x {}^{2} - 7 = 0 \\ x - 2 - x {}^{2} = 0 \\ - x {}^{2} + x - 2 = 0 \\ x {}^{2} - x + 2 = 0 \\ x = \frac{ - ( - 1) + - \sqrt{( - 1) {}^{2} - 4 \times 1 \times 2} }{2 \times 1} \\ \\ x = \frac{1 + - \sqrt{1 - 8} }{2} \\ \\ x = \frac{1 + - \sqrt{ - 7} }{2}$

Ответ : В действительных числах корней нет : х € R

________________________________

Корень из : - 7 = 7i

==>

x = ( 1 - + 7i ) ÷ 2

x1 = ( 1 - 7i ) ÷ 2

x1 = 1/2 - 7/2i

x1 = 0,5 - 3,5i

----------------------------------

x2 = ( 1 + 7i) ÷ 2

x2 = 1/2 - 7/2i

x2 = 0,5 + 3,5i

---------------------------------

Ответ :

• х1 = 0,5 - 3,5i

• x2 = 0,5 + 3,5i

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