Ответ:
-12
Объяснение:
y' = (4x(x+1)-(2x^2+6))/(x+1)^2 = (2х^2+4х-6)/(х+1)^2 = 2(x+3)(x-1)/(x+1)^2 = 0
x = -3; x = 1 - не належить проміжку [-5; -2]
f(-5) = -14
f(-3) = -12
f(-2) = -14
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Answers & Comments
Ответ:
-12
Объяснение:
y' = (4x(x+1)-(2x^2+6))/(x+1)^2 = (2х^2+4х-6)/(х+1)^2 = 2(x+3)(x-1)/(x+1)^2 = 0
x = -3; x = 1 - не належить проміжку [-5; -2]
f(-5) = -14
f(-3) = -12
f(-2) = -14