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1Sweg1
@1Sweg1
August 2021
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х^2-12х+20 разложите на множители
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holmskaja
X^2-12x+20=0
D=b^2-4ac=(-12)^2-4*20=144-80=64
x1,2=-b+-корень D:2a
x1,2=12+-8: 2
x1=10
x2=2
(x-10)(x-2)=0
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Answers & Comments
D=b^2-4ac=(-12)^2-4*20=144-80=64
x1,2=-b+-корень D:2a
x1,2=12+-8: 2
x1=10
x2=2
(x-10)(x-2)=0