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кратохвил
@кратохвил
July 2022
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х^2 - 4x + 2x - 8 ≤ 0
Решите неравенство. Помогите пожалуйста!
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milasuper1999
X²-4x+2x-8≤0
(x²-4x)+(2x-8)≤0
x(x-4)+2(x-4)≤0
(x-4)(x+2)≤0
x-4≤0 x+2≤0
x≥4 x ≤ -2
Ответ: [-2, 4]
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Answers & Comments
(x²-4x)+(2x-8)≤0
x(x-4)+2(x-4)≤0
(x-4)(x+2)≤0
x-4≤0 x+2≤0
x≥4 x ≤ -2
Ответ: [-2, 4]