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alshko
@alshko
March 2022
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сократить дробь: а) х^3-х^2/х^2
б) х^2-3х/х^2-9
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LANAOVICH
а) (х
³
-х
²)
/х
²=x²(x-1)/x²=сокращаем, получаем=x-1
б) (х
²
-3х)/(х
²
-9)=x(x-3)/(x-3)(x+3)=x/x+3
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alshko
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Answers & Comments
б) (х²-3х)/(х²-9)=x(x-3)/(x-3)(x+3)=x/x+3