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00angel
@00angel
August 2022
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х^(2)-х+9+√(х^(2)-х+9)=12
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Ulchikteacher
Решаешь методом замены
1 votes
Thanks 1
hovsep50
√(x²-x+9) = y : y≥0 ⇒ y² +y = 12
y²+y-12=0
(y - 3)(y+4) =0 ⇒ y1 =3 ; y2 = -4 не уд. ⇒
√( x² -x +9) = 3
x² - x = 0
x(x-1)=0
x1=0 ; x2 = 1
2 votes
Thanks 1
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Answers & Comments
y²+y-12=0
(y - 3)(y+4) =0 ⇒ y1 =3 ; y2 = -4 не уд. ⇒
√( x² -x +9) = 3
x² - x = 0
x(x-1)=0
x1=0 ; x2 = 1