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well200130
@well200130
November 2021
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-х2+3х-2<0, пожалуйста)
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Froggger
Умножим на -1
X^2-3x+2>0
X1=2 x2=1
X є (-бесконечности;1)U(2;+бесконечности)
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НоВыЙ13
-x^2+3x-2<0 |*(-1)
x^2-3x+2>0
D=9-4*2=1
X1,2 = 3+/-1 / 2 = 2; 1
x1=2 ; x2=1
+ - +
------o---------o---------
1 2
x∈(-∞;1)U(2;+∞) <--------- ответ!
1 votes
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Answers & Comments
X^2-3x+2>0
X1=2 x2=1
X є (-бесконечности;1)U(2;+бесконечности)
x^2-3x+2>0
D=9-4*2=1
X1,2 = 3+/-1 / 2 = 2; 1
x1=2 ; x2=1
+ - +
------o---------o---------
1 2
x∈(-∞;1)U(2;+∞) <--------- ответ!