х^2+4х+4...

ProstoSempai @ProstoSempai

July 2022 1 6 Report

упростите выражение (2/х^2-4+1/2x-x^2):1/х^2+4х+4

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hote

Verified answer

$\displaystyle ( \frac{2}{(x^2-4)}+ \frac{1}{2x-x^2}): \frac{1}{x^2+4x+4}=$

$\displaystyle ( \frac{2}{(x-2)(x+2)}+ \frac{1}{x(2-x)})* (x+2)^2=$

$\displaystyle ( \frac{2}{(x-2)(x+2)}+ \frac{1}{-x(x-2)})*(x+2)^2 =$

$\displaystyle \frac{2x-(x+2)}{x(x-2)(x+2)}* (x+2)^2= \frac{x-2}{x(x-2)(x+2)}*(x+2)^2=$

$\displaystyle \frac{1}{x(x+2)}*(x+2)^2= \frac{x+2}{x}$

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