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kuroakiyamaoyn894
@kuroakiyamaoyn894
July 2022
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х^2+5*|х|+4=0 помогите решить пожалуйста
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Ainrkaden
Если х > 0 или х = 0
х^2 + 5х + 4 = 0
х^2 + х + 4х + 4 =0
х(х + 1) + 4(х +1) = 0
(х + 1)(х + 4) = 0
х = -1 или -4
если х < 0
х^2 - 5х + 4 = 0
х^2 - х - 4х + 4 =0
х(х - 1) - 4(х - 1) = 0
(х - 1)( х - 4) = 0
х = 1 или 4
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Thanks 2
MarIceTeam
Х²+5|х|+4=0
1. х≥0
х²+5х+4=0;
По теореме Виета:
х1+х2=-5
х1·х2=4
х1=-4
х2=-1
2. х<0
х²-5х+4=0
По теореме Виета:
х1+х2=5
х1·х2=4
х1=4
х2=1
Ответ: -4, -1, 1, 4.
Удачи
1 votes
Thanks 1
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Answers & Comments
х^2 + 5х + 4 = 0
х^2 + х + 4х + 4 =0
х(х + 1) + 4(х +1) = 0
(х + 1)(х + 4) = 0
х = -1 или -4
если х < 0
х^2 - 5х + 4 = 0
х^2 - х - 4х + 4 =0
х(х - 1) - 4(х - 1) = 0
(х - 1)( х - 4) = 0
х = 1 или 4
1. х≥0
х²+5х+4=0;
По теореме Виета:
х1+х2=-5
х1·х2=4
х1=-4
х2=-1
2. х<0
х²-5х+4=0
По теореме Виета:
х1+х2=5
х1·х2=4
х1=4
х2=1
Ответ: -4, -1, 1, 4.
Удачи