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gevorgyan13
@gevorgyan13
July 2022
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Числа x1 и х2 являются корнями уравнения х^2-6x+3=0. Найдите значения выражения 1/x1+1/х2
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movgoen
D = b^2 - 4ac = 24
x₁ = (6 - 2√8)/2
x₂ = (6 + 2√8)/2
1/x₁ + 1/x₂ = 2/(6-2√8) + 2/(6+2√8) =
=
= 24/24 = 1
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Answers & Comments
x₁ = (6 - 2√8)/2
x₂ = (6 + 2√8)/2
1/x₁ + 1/x₂ = 2/(6-2√8) + 2/(6+2√8) = = = 24/24 = 1