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alesha92067
@alesha92067
August 2022
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H2+B2r=2HBr - схема перехода электронов
4P+502=2P2O5 - схема перехода электронов
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zubareva45
Verified answer
H₂⁰+Br₂⁰⇒H⁺Br⁻
2H⁰ - 2хe⁻ ⇒2H⁺ 2
2Br⁰ +2хe⁻ ⇒Br⁻ 2
H₂+Br₂=2HBr
P
⁰+O₂⁰⇒P₂⁺⁵O₅⁻²
P⁰ - 5e⁻⇒P⁺⁵ 5 4
20
2O⁰ + 2x2e⁻⇒2O⁻² 4 5
4P + 5O₂ = 2P₂O₅
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Answers & Comments
Verified answer
H₂⁰+Br₂⁰⇒H⁺Br⁻2H⁰ - 2хe⁻ ⇒2H⁺ 2
2Br⁰ +2хe⁻ ⇒Br⁻ 2
H₂+Br₂=2HBr
P⁰+O₂⁰⇒P₂⁺⁵O₅⁻²
P⁰ - 5e⁻⇒P⁺⁵ 5 4
20
2O⁰ + 2x2e⁻⇒2O⁻² 4 5
4P + 5O₂ = 2P₂O₅