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Agamble
@Agamble
August 2022
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Освободитесь от иррациональности в знаменателе дроби:
3а/√5,
3х/√х+2.
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s0807
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=
=\frac{3\sqrt{x+2} }{{x+2}[/tex]
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==
=\frac{3\sqrt{x+2} }{{x+2}[/tex]