Ответ:
H2O3=2×1+16×3=2+48=50
BaCO3=137+12+3×16=149+48=197
2Ca3PO4=2×(3×40+31+4×16)=2×(120+31+64)=2×215=430
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Ответ:
H2O3=2×1+16×3=2+48=50
BaCO3=137+12+3×16=149+48=197
2Ca3PO4=2×(3×40+31+4×16)=2×(120+31+64)=2×215=430