Ответ:

Объяснение:

Аr(H2SO4)= 2 * 1 + 32 + 4* 16 = 98г/моль

w(H) = (2 * 1)/98 = 2,04%

w(S) = 32/98 = 32,65%

w(O) = (4*16)/98 = 65,3%

Аr(KOH) = 39 + 16 + 1 = 56г/моль

w(H) = 1/56 = 1,78%

w(К) = 39/56 = 69,65%

w(O) = 16/56 = 28,57%

Аr(СО2) = 12 + 16 * 2 = 44г/моль

w(С) = 12/44 = 27,27%

w(О) = 2 * 16/44 = 72,73%

Аr(NO) = 14 + 16 = 30г/моль

w(N) = 14/30 = 46,67%

w(О) = 16/30 = 53,33%