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rsleptsov
@rsleptsov
September 2021
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избавьтесь от иррациональности в знаменателе дроби:
х+1
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\/х+3 -2
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MizoriesKun
Х+1 (х+1)*(√(х+3) +2) (х+1)*(√(х+3) +2)
-------------- = ------------------------------------- = ------------------------------- =
√(х+3) -2 (√(х+3) -2)(√(х+3) +2) (√(х+3)² -2²)
(х+1)*(√(х+3) +2) (х+1)*(√(х+3) +2)
= -------------------------------- = -----------------------------
х+3- 4 х-1
2 votes
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Answers & Comments
-------------- = ------------------------------------- = ------------------------------- =
√(х+3) -2 (√(х+3) -2)(√(х+3) +2) (√(х+3)² -2²)
(х+1)*(√(х+3) +2) (х+1)*(√(х+3) +2)
= -------------------------------- = -----------------------------
х+3- 4 х-1