sangers1959

Verified answer

-17/((x+3)²-7)≥0
-17/(x²+6x+9-7)≥0
-17/(x²+6x+2)≥0   |÷(-17)
1/(x²+6x+2)≤0   ⇒
x²+6x+2<0   D=28
x₁=-3-√7    x₂=-3+√7
(x+3+√7)(x-3-√7)<0
-∞______+_______-3-√7_______-_______-3+√7______+______+∞
Ответ: x∈(-3-√7;-3+√7).