Home
О нас
Products
Services
Регистрация
Войти
Поиск
Манашева
@Манашева
July 2022
1
8
Report
Решить уравнение -6/х^2-9-х+1/х-3=1/х+3
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
litanalove
Verified answer
-6/(x-3)(x+3) -(x+1)/(x-3) =1/(x+3)
(-6 -(x+1)(x+3)) /(x-3)(x+3) =1/(x+3)
(-6 -(x²+3x+x+3))/(x-3)(x+3) =1/(x+3)
(-6 -x² -4x -3)/(x-3)(x+3) -1/(x+3) =0
(-9 -x² -4x -(x-3)) /(x-3)(x+3) =0
-9 -x² -4x -x +3 =0
-x² -5x -6 =0, *(-1)
x² +5x +6 =0
D =b² -4ac
(a=1, b=5, c=6)
D =25 -4*6 =1
x1,x2=(-b+-корень изD)/2a
x1 =(-5 -1)/2 = -3
x2 =(-5 +1)/2 = -2
ответ: x= -2, x= -3
6 votes
Thanks 4
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "х+3..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
-6/(x-3)(x+3) -(x+1)/(x-3) =1/(x+3)(-6 -(x+1)(x+3)) /(x-3)(x+3) =1/(x+3)
(-6 -(x²+3x+x+3))/(x-3)(x+3) =1/(x+3)
(-6 -x² -4x -3)/(x-3)(x+3) -1/(x+3) =0
(-9 -x² -4x -(x-3)) /(x-3)(x+3) =0
-9 -x² -4x -x +3 =0
-x² -5x -6 =0, *(-1)
x² +5x +6 =0
D =b² -4ac
(a=1, b=5, c=6)
D =25 -4*6 =1
x1,x2=(-b+-корень изD)/2a
x1 =(-5 -1)/2 = -3
x2 =(-5 +1)/2 = -2
ответ: x= -2, x= -3