(х+4)(х-3)+(х-5)(х+4)=0 решить уравнение
x^2-3x+4x-12+x^2+4x-5x-20=0
2x^2-32=0 | :2
х^2-16=0
x^2=16
x= + -4
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x^2-3x+4x-12+x^2+4x-5x-20=0
2x^2-32=0 | :2
х^2-16=0
x^2=16
x= + -4