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amirratmir
@amirratmir
August 2021
1
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пожалуйста помогите. Выполните действия: 1) (x/2-х/3)*5/х^2;
2) y^2/4*(у/5-2/у^2);
3)(1/х+1/У):2/ху.
4.) 12х/х-у :(х/6 - у/6)
5) 15х/х+у * (1/3 + у/х)
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selmash21
1)
х(1/2-1/3)×5/х^2=(3/6-2/6)×5/х=1/6×5/х=5/6х
2)
у^2/4×((у^3-10)/5у^2)=
=у^2×(у^3-10)/20у^2=(у^3-10)/20
3)
(1/х+1/у)÷2/ху=((у+х)/ху)÷2/ху=
(у+х)×ху
=---------------=(у+х)/2
ху×2
4)=12/(х-у) ÷((х-у)/6)=
12×6
=-----------=72/(х-у)^2
(х-у)(х-у)
5)
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Answers & Comments
х(1/2-1/3)×5/х^2=(3/6-2/6)×5/х=1/6×5/х=5/6х
2)
у^2/4×((у^3-10)/5у^2)=
=у^2×(у^3-10)/20у^2=(у^3-10)/20
3)
(1/х+1/у)÷2/ху=((у+х)/ху)÷2/ху=
(у+х)×ху
=---------------=(у+х)/2
ху×2
4)=12/(х-у) ÷((х-у)/6)=
12×6
=-----------=72/(х-у)^2
(х-у)(х-у)
5)